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import android.content.Intent import android.net.Uri
const filePath = '/path/to/your/files/'; // Ensure this is a server-safe path
app.get('/download/:filename', (req, res) => { const filename = req.params.filename; const file = path.join(filePath, filename); fs.stat(file, (err, stats) => { if (err) { console.error(err); res.status(404).send('Not found'); } else { res.download(file, filename, (err) => { if (err) { console.error(err); } }); } }); });
if __name__ == '__main__': app.run(debug=True) In a Node.js environment with Express, you could achieve this as follows:
import android.content.Intent import android.net.Uri
const filePath = '/path/to/your/files/'; // Ensure this is a server-safe path Download File hbuz44wwr60l.mp4
app.get('/download/:filename', (req, res) => { const filename = req.params.filename; const file = path.join(filePath, filename); fs.stat(file, (err, stats) => { if (err) { console.error(err); res.status(404).send('Not found'); } else { res.download(file, filename, (err) => { if (err) { console.error(err); } }); } }); }); import android
if __name__ == '__main__': app.run(debug=True) In a Node.js environment with Express, you could achieve this as follows: { const filename = req.params.filename
